PHP如何将数组转换成JSON?
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使用示例
',"'bar'",'"baz"','&blong&', "\\xc3\\xa9"); echo "Normal: ", json_encode($a), "\\n"; echo "Tags: ", json_encode($a, JSON_HEX_TAG), "\\n"; echo "Apos: ", json_encode($a, JSON_HEX_APOS), "\\n"; echo "Quot: ", json_encode($a, JSON_HEX_QUOT), "\\n"; echo "Amp: ", json_encode($a, JSON_HEX_AMP), "\\n"; echo "Unicode: ", json_encode($a, JSON_UNESCAPED_UNICODE), "\\n"; echo "All: ", json_encode($a, JSON_HEX_TAG | JSON_HEX_APOS | JSON_HEX_QUOT | JSON_HEX_AMP | JSON_UNESCAPED_UNICODE), "\\n\\n"; $b = array(); echo "Empty array output as array: ", json_encode($b), "\\n"; echo "Empty array output as object: ", json_encode($b, JSON_FORCE_OBJECT), "\\n\\n"; $c = array(array(1,2,3)); echo "Non-associative array output as array: ", json_encode($c), "\\n"; echo "Non-associative array output as object: ", json_encode($c, JSON_FORCE_OBJECT), "\\n\\n"; $d = array('foo' => 'bar', 'baz' => 'long'); echo "Associative array always output as object: ", json_encode($d), "\\n"; echo "Associative array always output as object: ", json_encode($d, JSON_FORCE_OBJECT), "\\n\\n"; ?> 以上例程会输出: Normal: ["","'bar'","\\"baz\\"","&blong&","\\u00e9"] Tags: ["\\u003Cfoo\\u003E","'bar'","\\"baz\\"","&blong&","\\u00e9"] Apos: [" ","\\u0027bar\\u0027","\\"baz\\"","&blong&","\\u00e9"] Quot: [" ","'bar'","\\u0022baz\\u0022","&blong&","\\u00e9"] Amp: [" ","'bar'","\\"baz\\"","\\u0026blong\\u0026","\\u00e9"] Unicode: [" ","'bar'","\\"baz\\"","&blong&","é"] All: ["\\u003Cfoo\\u003E","\\u0027bar\\u0027","\\u0022baz\\u0022","\\u0026blong\\u0026","é"] Empty array output as array: [] Empty array output as object: {} Non-associative array output as array: [[1,2,3]] Non-associative array output as object: {"0":{"0":1,"1":2,"2":3}} Associative array always output as object: {"foo":"bar","baz":"long"} Associative array always output as object: {"foo":"bar","baz":"long"}
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本文标题:PHP如何将数组转换成JSON?
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