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关于python时间日期函数的信息

python数字怎么转变时间?

5位数日期戳读取 .mat 文件处理里面数据时,发现里面的日期数据全部都是 “5位数” 数字,很不解;后来查到可以在excel中通过设置单元格调回标准日期格式,如下:选中日期戳,右键选择 “格式化单元格(Format Cells)”选择需要的日期格式,点击ok即可通过代码转成标准日期例如这个DataFrame中的日期,全部都是“日期戳”格式的,但我需要的是人能看懂的“标准日期”;确认起始日期首先需拿一个“日期戳”对应的时间(标准日期),减去这个日期戳,得出起始时间。获取起始时间:2018-05-02 对应的日期戳为:43222,接下来通过pandas 的Timedelta()和 to_datetime() 获取起始时间。可以看到起始日期为“1899-12-30”这样一来后续日期戳转标准日期,只需要在 “1899-12-30” 的基础上加 “日期戳”即可。批量转换首先定义一个函数用来进行转换:#定义转化日期戳的函数,stamp为日期戳def date(stamp):delta = pd.Timedelta(str(stamp)+'D')real_time = pd.to_datetime('1899-12-30') + deltareturn real_time然后针对DataFrame需要转换的列进行转换即可:

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Python123上面有关datetime库函数的使用的一道程序题求助

按照题目要求编写的Python程序如下

from datetime import datetime

day=input()

day1=list(map(int,day.split(',')))

x=datetime(day1[0],day1[1],day1[2],day1[3],day1[4])

week=x.weekday()

print("这一天是星期{}。".format(week+1))

timestamp=datetime.timestamp(x)

utc=datetime.utcfromtimestamp(timestamp)

print("这一天的UTC时间是{}。".format(utc.isoformat()))

print(x.strftime('这一天是%b月--%d日--%Y年,%I点%M分%p。'))

python 怎么定义一个函数,输出日历

import re

def command_add(date, event_details, calendar):

'''

Add event_details to the list at calendar[date]

Create date if it was not there

:param date: A string date formatted as "YYYY-MM-DD"

:param event_details: A string describing the event

:param calendars: The calendars database

:return: a string indicating any errors, "" for no errors

'''

try:

p = re.compile(r"\d{4}-\d{2}-\d{2}")

assert p.match(date), "Param date must match YYYY-MM-DD"

assert isinstance(event_details, str), \

"Param event_details must be a string"

if date in calendar:

calendar[date].append(str(event_details))

else:

calendar.update({date: str(event_details)})

except Exception,e:

return str(e)

def main():

calendar = {}

command_add("2015-10-20", "Python class", calendar)

print calendar

command_add("2015-11-01", "go out with friends after test",

calendar)

print calendar

if __name__ == "__main__":

main()

python中,怎么把字符串转换为日期格式

python中要把字符串转换成日期格式需要使用time模块中的strptime函数,例子如下:

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import time

t = time.strptime('2016-05-09 21:09:30', '%Y-%m-%d %H:%M:%S')

print(t)

执行结果如下:

time.struct_time(tm_year=2016, tm_mon=5, tm_mday=9, tm_hour=21, tm_min=9, tm_sec=30, tm_wday=0, tm_yday=130, tm_isdst=-1)

函数说明:

第一个参数是要转换成日期格式的字符串,第二个参数是字符串的格式

函数官方文档如下:

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Help on built-in function strptime in module time:

strptime(...)

strptime(string, format) - struct_time

Parse a string to a time tuple according to a format specification.

See the library reference manual for formatting codes (same as

strftime()).

Commonly used format codes:

%Y Year with century as a decimal number.

%m Month as a decimal number [01,12].

%d Day of the month as a decimal number [01,31].

%H Hour (24-hour clock) as a decimal number [00,23].

%M Minute as a decimal number [00,59].

%S Second as a decimal number [00,61].

%z Time zone offset from UTC.

%a Locale's abbreviated weekday name.

%A Locale's full weekday name.

%b Locale's abbreviated month name.

%B Locale's full month name.

%c Locale's appropriate date and time representation.

%I Hour (12-hour clock) as a decimal number [01,12].

%p Locale's equivalent of either AM or PM.

Other codes may be available on your platform. See documentation for the C library strftime function.


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