这篇文章给大家分享的是有关C语言如何实现对对碰游戏的内容。小编觉得挺实用的,因此分享给大家做个参考,一起跟随小编过来看看吧。
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本文实例为大家分享了C语言对对碰游戏的具体代码,供大家参考,具体内容如下
//////////////////////////////////////// //画素材的x和y都是反的,因为x表示行,但是画出来x表示列,y同 //////////////////////////////////////// #include#include #include #include #include #include #pragma comment(lib, "Winmm.lib") using namespace std; /***************定义枚举类型*****************/ enum color{blank, red, yellow, blue, green, white, orange, purple, shizijia, zhadan, qicai, alarm}; /***************定义全局变量***************/ const int MaxT = 12; // 时间上限 const int T = 10 * MaxT;// 时间速度 const int V = 300; // 停留时间 clock_t start, now; // 控制时间 color gem[9][8]; // 地图 // IMAGE对象 IMAGE img[12], music_img[2], exit_img, jindutiao; int Score, Time; // 成绩 时间 bool Flag, Music = true;// 是否加载 音乐 /*******************函数声明******************/ void load(void); // 加载IMAGE对象 void Blank(void); // 清空 bool soso(void); // 搜索空格 bool baidu(void); // 搜索解法 void New(void); // 更新 void print(void); // 输出 bool judge(void); // 判断是否可以消除 void fall(void); // 下落 void draw(void); // 消除 bool quit(void); // 是否重新开始 void play(void); // 游戏过程 /********************定义函数****************/ void load(void) { char c[20]; int i; // 加载IMAGE对象 for (i = 0; i < 12; i++) { ostrstream strout(c, 50); strout <<"图片\\" <>Flag >>Music; if (Flag) { HWND wnd = GetHWnd(); SetWindowText(wnd, "对对碰"); if (MessageBox(wnd, "是否继续上次游戏?", "游戏开始", MB_YESNO | MB_ICONQUESTION) == IDYES) { fin >>Score >>Time; for (i = 0; i < 9; i++) for (int j = 0; j < 8; j++) { int t; fin >>t; gem[i][j] = color(t); } } else Flag = false; } fin.close(); } void Blank(void) { for (int i = 1; i < 9; i++) for (int j = 0; j < 8; j++) gem[i][j] = blank; print(); fall(); } bool soso(void) { for (int i = 1; i < 9; i++) for (int j = 0; j < 8; j++) if (gem[i][j] == blank) return true; return false; } bool baidu(void) { int i, j; color t; bool flag = false; // 如果有一个道具则返回真 for (i = 1; i < 9; i++) for (j = 0; j < 8; j++) if (gem[i][j] >= shizijia) return true; // 搜索解法 for (i = 1; i < 9; i++) for (j = 0; j < 7; j++) { t = gem[i][j]; gem[i][j] = gem[i][j + 1]; gem[i][j + 1] = t; if (judge()) flag = true; t = gem[i][j]; gem[i][j] = gem[i][j + 1]; gem[i][j + 1] = t; if (flag) return true; } for (i = 1; i < 7; i++) for (j = 0; j < 8; j++) { t = gem[i][j]; gem[i][j] = gem[i + 1][j]; gem[i + 1][j] = t; if (judge()) flag = true; t = gem[i][j]; gem[i][j] = gem[i + 1][j]; gem[i + 1][j] = t; if (flag) return true; } return false; } void New(void) { static int old_score = -1, old_time = T; bool flag = false; if (Score != old_score) // 更新分数 { if (Score > 999999999) { if (MessageBox(GetHWnd(), "恭喜你达到了最高分!\n是否重新开始?", "游戏结束", MB_YESNO | MB_ICONQUESTION) == IDYES) Score = 0; else exit(0); } char s[15]; ostrstream strout(s, 15); strout <<'$' < old_time) putimage(540, 140, &jindutiao); setcolor(BLACK); for (int i = 0; i < T - Time; i++) { line(540, 140 + 2 * i, 580, 140 + 2 * i); line(540, 140 + 2 * i + 1, 580, 140 + 2 * i + 1); } old_time = Time; flag = true; } if (flag) // 写存档 { ofstream fout("存档.dat"); fout < = 1; i--) if (gem[i][j] == blank) { a[j] = i; sign = true; break; } if (sign == false) return; IMAGE im[8]; for (j = 0; j < 8; j++) if (a[j] > 1) getimage(&im[j], 60 * j, 0, 60, 60 * (a[j] - 1)); for (i = 0; i < 60 ; i += 2) for (j = 0; j < 8; j++) if (a[j] > 0) { if (a[j] > 1) putimage(60 * j, i + 2, &im[j]); putimage(60 * j, i + 2 - 60, &img[int(gem[0][j])]); Sleep(1); } for (j = 0; j < 8; j++) if (a[j] > 0) { for (i = a[j]; i > 0; i--) gem[i][j] = gem[i - 1][j]; if (rand() % 50 == 0) gem[0][j] = color(rand() % 4 + 8); else gem[0][j] = color(rand() % 7 + 1); } } // 加对大括号使递归时撤销内存空间 if (soso()) fall(); if (judge()) draw(); } void draw(void) { { int i, j; bool a[9][8] = {false}; for (i = 1; i < 9; i++) for (j = 0; j < 6; j++) if (gem[i][j] == gem[i][j + 1] && gem[i][j] == gem[i][j + 2]) a[i][j] = a[i][j + 1] = a[i][j + 2] = true; for (i = 1; i < 7; i++) for (j = 0; j < 8; j++) if (gem[i][j] == gem[i + 1][j] && gem[i][j] == gem[i + 2][j]) a[i][j] = a[i + 1][j] = a[i + 2][j] = true; for (i = 1; i < 9; i++) for (j = 0; j < 8; j++) if (a[i][j]) { gem[i][j] = blank; Score += 10; } Sleep(V); Time += T / MaxT; if (Time > T) Time = T; print(); } // 加对大括号使递归时撤销内存空间 fall(); } bool quit(void) { char str[50]; ostrstream strout(str, 50); strout <<"得分:" < T) Time = T; print(); Sleep(V); fall(); if (!baidu()) Blank(); break; case zhadan: if (x > 1) { gem[x - 1][y] = blank; Score += 10; if (y > 0) { gem[x - 1][y - 1] =blank; Score += 10; } } if (y > 0) { gem[x][y - 1] = blank; if (x < 8) { gem[x + 1][y - 1] =blank; Score += 10; } } if (x < 8) { gem[x + 1][y] = blank; if (y < 7) { gem[x + 1][y + 1] =blank; Score += 10; } } if (y < 7) { gem[x][y + 1] = blank; if (x > 1) { gem[x - 1][y + 1] =blank; Score += 10; } } gem[x][y] = blank; Time += T / MaxT; if (Time > T) Time = T; print(); Sleep(V); fall(); if (!baidu()) Blank(); break; case qicai: t = color(rand() % 7 + 1); putimage(60 * y, 60 * (x - 1), &img[int(t)]); Sleep(V); for (i = 1; i < 9; i++) for (j = 0; j < 8; j++) if (gem[i][j] == t) { gem[i][j] = blank; putimage(60 * j, 60 * (i - 1), &img[0]); Score += 10; } gem[x][y] = blank; Time += T / MaxT; if (Time > T) Time = T; print(); fall(); if (!baidu()) Blank(); break; case alarm: Time = T; gem[x][y] = blank; print(); fall(); if (!baidu()) Blank(); break; } break; } else if (x1 > 480 && x1 < 560 && y1 > 400 && y1 < 480) { if (Music) mciSendString("stop mymusic", NULL, 0, NULL); else mciSendString("play mymusic from 0 repeat", NULL, 0, NULL); Music = !Music; putimage(480, 400, &music_img[int(Music)]); } else if (x1 > 560 && x1 < 640 && y1 > 400 && y1 < 480) exit(0); } } now = clock(); if (now - start >= CLOCKS_PER_SEC * MaxT / T) { start = now; Time--; New(); if (Time <= 0) return; } } while (m.mkLButton && m.y < 480) { m = GetMouseMsg(); x = m.x; y = m.y; if (x - x1 > 30 || x1 - x > 30 || y - y1 > 30 || y1 - y > 30) { sign = false; break; } now = clock(); if (now - start >= CLOCKS_PER_SEC * MaxT / T) { start = now; Time--; New(); if (Time <= 0) return; } } if(sign) { putimage(x1 - x1 % 60, y1 - y1 % 60, &img[int(gem[y1 / 60 + 1][x1 / 60])], SRCPAINT); continue; } if (y1 - y > 30 && y1 / 60 > 0) fx = 'u'; if (y - y1 > 30 && y1 / 60 < 7) fx = 'd'; if (x1 - x > 30 && x1 / 60 > 0) fx = 'l'; if (x - x1 > 30 && x1 / 60 < 7) fx = 'r'; x = y1 / 60 + 1; y = x1 / 60; x1 = y1 = 0; switch (fx) { case 'u':x1 = -1; break; case 'd':x1 = 1; break; case 'l':y1 = -1; break; case 'r':y1 = 1; break; case '\0':continue; } for (i = 0; i < 60;) { putimage(60 * y, 60 * (x - 1), &img[0]); putimage(60 * y, 60 * (x - 1), &img[0]); i += 1; putimage(60 * (y + y1) - i * y1, 60 * (x - 1 + x1) - i * x1, &img[int(gem[x + x1][y + y1])]); putimage(60 * y + i * y1, 60 * (x - 1) + i * x1, &img[int(gem[x][y])]); Sleep(2); } t = gem[x][y]; gem[x][y] = gem[x + x1][y + y1]; gem[x + x1][y + y1] = t; if (judge()) { draw(); if (!baidu()) Blank(); } else { for (i = 0; i < 60;) { putimage(60 * y, 60 * (x - 1), &img[0]); putimage(60 * y, 60 * (x - 1), &img[0]); i += 1; putimage(60 * (y + y1) - i * y1, 60 * (x - 1 + x1) - i * x1, &img[int(gem[x + x1][y + y1])]); putimage(60 * y + i * y1, 60 * (x - 1) + i * x1, &img[int(gem[x][y])]); Sleep(2); } t = gem[x][y]; gem[x][y] = gem[x + x1][y + y1]; gem[x + x1][y + y1] = t; } now = clock(); if (now - start >= CLOCKS_PER_SEC * MaxT / T) { start = now; Time--; New(); if (Time <= 0) return; } }while (true); } /****************主函数******************/ int APIENTRY WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nCmdShow) { try { // 加载素材 load(); } catch (int) { ofstream fout("存档.dat"); fout < 感谢各位的阅读!关于“C语言如何实现对对碰游戏”这篇文章就分享到这里了,希望以上内容可以对大家有一定的帮助,让大家可以学到更多知识,如果觉得文章不错,可以把它分享出去让更多的人看到吧!
文章名称:C语言如何实现对对碰游戏
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